What is the total capacitance of two capacitors in series if the first is 25MFD at 440VAC and the second is 35MFD at 440VAC?

To determine the total capacitance of capacitors in series, the formula used is:

1 / C_total = 1 / C1 + 1 / C2

Where C1 and C2 are the capacitances of the individual capacitors. In this case, C1 is 25 MFD and C2 is 35 MFD.

Calculating it step-by-step:

1. Convert the values into fractions:

   • 1 / C1 = 1 / 25
   • 1 / C2 = 1 / 35

2. Find a common denominator and perform the calculations:

   • The least common multiple of 25 and 35 is 175. Therefore: 1 / C_total = (7 / 175) + (5 / 175) = (7 + 5) / 175 = 12 / 175

3. Now, taking the reciprocal to get C_total:

   • C_total = 175 / 12 ≈ 14.5833 MFD.

This rounds to approximately 14.58 MFD.

As for the voltage rating, capacitors in series have the same voltage across the entire series connection, so the voltage rating remains